In a 4-ohm parallel speaker configuration, how many total ohms does the configuration yield?

In a parallel speaker configuration, the total resistance (or impedance) is calculated using the formula for two or more resistors (or speakers) connected in parallel. When multiple speakers of the same impedance are connected in parallel, the total impedance can be found using the formula:

[ \frac{1}{Z_{total}} = \frac{1}{Z_1} + \frac{1}{Z_2} + \frac{1}{Z_3} + ... ]

In this case, when you have multiple 4-ohm speakers connected in parallel, the formula simplifies. For two 4-ohm speakers:

[ \frac{1}{Z_{total}} = \frac{1}{4} + \frac{1}{4} = \frac{2}{4} ]

Thus, solving for ( Z_{total} ):

[ Z_{total} = \frac{4}{2} = 2 , \text{Ohms} ]

If there are more than two speakers, the total impedance would continue to decrease. Consequently, in a scenario where two 4-ohm speakers are wired in parallel, you would indeed achieve a total impedance of 2 Ohms. As such, this